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Writer's pictureUttkarsh Kohli

An Alternative to Solving Quadratics

Updated: May 18, 2020

Quadratic equations.

We have all learnt about them in school and not all of us enjoyed solving them.

Partially because of the tidious formula invented 1400 years ago!

Which is (-b±√b²-4ac)/2a for the standard equation ax² + bx + c = 0 (a≠0)

Not everyone may be able to remember this formula.


So for those of you who cant! here is a new and simple way-

ax² + bx + c = 0 (a≠0)

Divide both sides a

x² + bx/a + c/a = 0

or

x² + Bx + C = 0 (B and C are constants)

lets take 2 variables m and n as the roots


The average of these two roots should be equal to -B/2.

The product of these two roots should be equal to C.

To get the average of -B/2, we can have m equal to -B/2 + z and n equal to -B/2 - z

To get the product C, mn = C or (-B/2 + z)(-B/2 - z)


C = B²/4 - z²

z² = B²/4 - C

z = ±√(B²/4 - C)

x = -B/2 ± √(B²/4 - C)


By doing this, we have actually found the two roots m and n.

This method is easier because the trick is to not memorize anything, all you need to do is consider values for the roots = -B/2 ± z

Setting the product equal to C, and solving for z.

Example:

3x² + 18x + 36 = 0

dividing by a,

x² - 6x + 8 = 0

Average is 3. (-B/2)

m = (3+z), n = (3-z)

(3+z)(3-z) = 8 . (C)

9-z² = 8

z² = 9-8

z = ±1

m = 3+z = 4

n = 3-z = 2

Hence 2,4 are the roots.


This method was put together by Po-Shen Loh,

He has done his PhD in mathematics from the Princeton University and is currently the coach for the American IMO team.

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